Asymptotes 2

Graph of f(x) = (x^2 - 4x) / (x^2 - 16).

Sorry, the GeoGebra Applet could not be started. Please make sure that Java 1.4.2 (or later) is installed and active in your browser (Click here to install Java now)

There is a horizontal asymptote at y = 1, since the limit at +/- infinity of f(x) is 1.
There is a vertical asymptote at x = -4 since the limit at -4 from the right is -infinity and the limit at -4 from the left is +infinity.

Jason McCullough, Created with GeoGebra